(h-1)/3=(2h+1)/9

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Solution for (h-1)/3=(2h+1)/9 equation: 



(h-1)/3=(2h+1)/9

We move all terms to the left:

(h-1)/3-((2h+1)/9)=0

We calculate fractions


h/()+(-((2h+1)*3)/()=0



We calculate terms in parentheses: +(-((2h+1)*3)/(), so:

-((2h+1)*3)/(

We multiply all the terms by the denominator


-((2h+1)*3)



We calculate terms in parentheses: -((2h+1)*3), so:

(2h+1)*3

We multiply parentheses

6h+3

Back to the equation:

-(6h+3)



We get rid of parentheses

-6h-3

Back to the equation:

+(-6h-3)



We get rid of parentheses

h/()-6h-3=0

We multiply all the terms by the denominator


h-6h*()-3*()=0

We add all the numbers together, and all the variables

h-6h*()=0

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