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(4x+12)+(8x-4)+52=180
We move all terms to the left:
(4x+12)+(8x-4)+52-(180)=0
We add all the numbers together, and all the variables
(4x+12)+(8x-4)-128=0
We get rid of parentheses
4x+8x+12-4-128=0
We add all the numbers together, and all the variables
12x-120=0
We move all terms containing x to the left, all other terms to the right
12x=120
x=120/12
x=10
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