6(x+3)+4x=7(3x+2)-7

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Solution for 6(x+3)+4x=7(3x+2)-7 equation: 



6(x+3)+4x=7(3x+2)-7

We move all terms to the left:

6(x+3)+4x-(7(3x+2)-7)=0

We add all the numbers together, and all the variables

4x+6(x+3)-(7(3x+2)-7)=0

We multiply parentheses

4x+6x-(7(3x+2)-7)+18=0



We calculate terms in parentheses: -(7(3x+2)-7), so:

7(3x+2)-7

We multiply parentheses

21x+14-7

We add all the numbers together, and all the variables

21x+7

Back to the equation:

-(21x+7)



We add all the numbers together, and all the variables

10x-(21x+7)+18=0

We get rid of parentheses

10x-21x-7+18=0

We add all the numbers together, and all the variables

-11x+11=0

We move all terms containing x to the left, all other terms to the right

-11x=-11

x=-11/-11

x=1

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