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(4x+12)(4x+12)=5x+8
We move all terms to the left:
(4x+12)(4x+12)-(5x+8)=0
We get rid of parentheses
(4x+12)(4x+12)-5x-8=0
We multiply parentheses ..
(+16x^2+48x+48x+144)-5x-8=0
We get rid of parentheses
16x^2+48x+48x-5x+144-8=0
We add all the numbers together, and all the variables
16x^2+91x+136=0
a = 16; b = 91; c = +136;
Δ = b2-4ac
Δ = 912-4·16·136
Δ = -423
Delta is less than zero, so there is no solution for the equation
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