If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/8(-2x-12)=-5
We move all terms to the left:
1/8(-2x-12)-(-5)=0
Domain of the equation: 8(-2x-12)!=0We add all the numbers together, and all the variables
x∈R
1/8(-2x-12)+5=0
We multiply all the terms by the denominator
5*8(-2x-12)+1=0
Wy multiply elements
40x(-+1=0
We use the square of the difference formula
40x(-1=0
| X=3+5x-23 | | x–19=–23 | | 2/3=1/12d-1/2 | | -2.8k+0.7=-11.62 | | 4z^2-3z+11=3 | | 12bb=2 | | m+5=21= | | -99x(8+1=0 | | X-1.75=19x= | | 9+–b=14 | | y–8=5= | | E(x)=30+2.40x | | 9+(–b)=14 | | 103=70-7x+3x | | 145=1/2x | | 4x–3=3x+15 | | (-6)=j/2-8 | | 107+z=283 | | 7x5=3x+7 | | N=22t+15 | | −7x−33=4(−3x−7) | | 95=t+32 | | t/(-2)+6=5 | | 130=10x+50 | | 5y-12=8y | | 0=7n+6n | | 44=58‐8g | | -9=2g+1 | | x+19=–23 | | 132=-7x4(5x+7) | | 7x=18–2x. | | y-2=6.y=8 |