(4x+112)-4x=(9x+72)-4x

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Solution for (4x+112)-4x=(9x+72)-4x equation: 



(4x+112)-4x=(9x+72)-4x

We move all terms to the left:

(4x+112)-4x-((9x+72)-4x)=0

We add all the numbers together, and all the variables

-4x+(4x+112)-((9x+72)-4x)=0

We get rid of parentheses

-4x+4x-((9x+72)-4x)+112=0



We calculate terms in parentheses: -((9x+72)-4x), so:

(9x+72)-4x

We add all the numbers together, and all the variables

-4x+(9x+72)

We get rid of parentheses

-4x+9x+72

We add all the numbers together, and all the variables

5x+72

Back to the equation:

-(5x+72)



We add all the numbers together, and all the variables

-(5x+72)+112=0

We get rid of parentheses

-5x-72+112=0

We add all the numbers together, and all the variables

-5x+40=0

We move all terms containing x to the left, all other terms to the right

-5x=-40

x=-40/-5

x=+8

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