(4x+1)=(6x-41)

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Solution for (4x+1)=(6x-41) equation: 



(4x+1)=(6x-41)

We move all terms to the left:

(4x+1)-((6x-41))=0

We get rid of parentheses

4x-((6x-41))+1=0



We calculate terms in parentheses: -((6x-41)), so:

(6x-41)

We get rid of parentheses

6x-41

Back to the equation:

-(6x-41)



We get rid of parentheses

4x-6x+41+1=0

We add all the numbers together, and all the variables

-2x+42=0

We move all terms containing x to the left, all other terms to the right

-2x=-42

x=-42/-2

x=+21

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