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f+15/9=3
We move all terms to the left:
f+15/9-(3)=0
determiningTheFunctionDomain f-3+15/9=0
We multiply all the terms by the denominator
f*9+15-3*9=0
We add all the numbers together, and all the variables
f*9-12=0
Wy multiply elements
9f-12=0
We move all terms containing f to the left, all other terms to the right
9f=12
f=12/9
f=1+1/3
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