(4r+8)/12=(5r-40)/5

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Solution for (4r+8)/12=(5r-40)/5 equation: 



(4r+8)/12=(5r-40)/5

We move all terms to the left:

(4r+8)/12-((5r-40)/5)=0

We calculate fractions


4r/()+(-((5r-40)*12)/()=0



We calculate terms in parentheses: +(-((5r-40)*12)/(), so:

-((5r-40)*12)/(

We multiply all the terms by the denominator


-((5r-40)*12)



We calculate terms in parentheses: -((5r-40)*12), so:

(5r-40)*12

We multiply parentheses

60r-480

Back to the equation:

-(60r-480)



We get rid of parentheses

-60r+480

Back to the equation:

+(-60r+480)



We get rid of parentheses

4r/()-60r+480=0

We multiply all the terms by the denominator


4r-60r*()+480*()=0

We add all the numbers together, and all the variables

4r-60r*()=0

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