2x-5(3x-2)=27

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Solution for 2x-5(3x-2)=27 equation: 



2x-5(3x-2)=27

We move all terms to the left:

2x-5(3x-2)-(27)=0

We multiply parentheses

2x-15x+10-27=0

We add all the numbers together, and all the variables

-13x-17=0

We move all terms containing x to the left, all other terms to the right

-13x=17

x=17/-13

x=-1+4/13

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