(4j)+1(50-j)=80

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Solution for (4j)+1(50-j)=80 equation: 



(4j)+1(50-j)=80

We move all terms to the left:

(4j)+1(50-j)-(80)=0

We add all the numbers together, and all the variables

4j+1(-1j+50)-80=0

We move all terms containing j to the left, all other terms to the right

4j+1(-1j+50)=80

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