7(6x-5)-4(7x-3)=37

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Solution for 7(6x-5)-4(7x-3)=37 equation: 



7(6x-5)-4(7x-3)=37

We move all terms to the left:

7(6x-5)-4(7x-3)-(37)=0

We multiply parentheses

42x-28x-35+12-37=0

We add all the numbers together, and all the variables

14x-60=0

We move all terms containing x to the left, all other terms to the right

14x=60

x=60/14

x=4+2/7

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