(4c-6)+5=(c-8)

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Solution for (4c-6)+5=(c-8) equation: 



(4c-6)+5=(c-8)

We move all terms to the left:

(4c-6)+5-((c-8))=0

We get rid of parentheses

4c-((c-8))-6+5=0



We calculate terms in parentheses: -((c-8)), so:

(c-8)

We get rid of parentheses

c-8

Back to the equation:

-(c-8)



We add all the numbers together, and all the variables

4c-(c-8)-1=0

We get rid of parentheses

4c-c+8-1=0

We add all the numbers together, and all the variables

3c+7=0

We move all terms containing c to the left, all other terms to the right

3c=-7

c=-7/3

c=-2+1/3

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