3(y+2)+0.5y=41

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Solution for 3(y+2)+0.5y=41 equation: 



3(y+2)+0.5y=41

We move all terms to the left:

3(y+2)+0.5y-(41)=0

We add all the numbers together, and all the variables

0.5y+3(y+2)-41=0

We multiply parentheses

0.5y+3y+6-41=0

We add all the numbers together, and all the variables

3.5y-35=0

We move all terms containing y to the left, all other terms to the right

3.5y=35

y=35/3.5

y=10

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