(4/5)s=20

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Solution for (4/5)s=20 equation:



(4/5)s=20
We move all terms to the left:
(4/5)s-(20)=0
Domain of the equation: 5)s!=0
s!=0/1
s!=0
s∈R
We add all the numbers together, and all the variables
(+4/5)s-20=0
We multiply parentheses
4s^2-20=0
a = 4; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·4·(-20)
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{5}}{2*4}=\frac{0-8\sqrt{5}}{8} =-\frac{8\sqrt{5}}{8} =-\sqrt{5} $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{5}}{2*4}=\frac{0+8\sqrt{5}}{8} =\frac{8\sqrt{5}}{8} =\sqrt{5} $

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