6(3x-2)=7x+3+4

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Solution for 6(3x-2)=7x+3+4 equation: 



6(3x-2)=7x+3+4

We move all terms to the left:

6(3x-2)-(7x+3+4)=0

We add all the numbers together, and all the variables

6(3x-2)-(7x+7)=0

We multiply parentheses

18x-(7x+7)-12=0

We get rid of parentheses

18x-7x-7-12=0

We add all the numbers together, and all the variables

11x-19=0

We move all terms containing x to the left, all other terms to the right

11x=19

x=19/11

x=1+8/11

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