(4/3x)+(2/3x)=13

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Solution for (4/3x)+(2/3x)=13 equation: 



(4/3x)+(2/3x)=13

We move all terms to the left:

(4/3x)+(2/3x)-(13)=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+4/3x)+(+2/3x)-13=0

We get rid of parentheses

4/3x+2/3x-13=0

We multiply all the terms by the denominator


-13*3x+4+2=0

We add all the numbers together, and all the variables

-13*3x+6=0

Wy multiply elements

-39x+6=0

We move all terms containing x to the left, all other terms to the right

-39x=-6

x=-6/-39

x=2/13

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