1/3(2x-5)+5=2/5(x-2)

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Solution for 1/3(2x-5)+5=2/5(x-2) equation: 



1/3(2x-5)+5=2/5(x-2)

We move all terms to the left:

1/3(2x-5)+5-(2/5(x-2))=0



Domain of the equation: 3(2x-5)!=0

x∈R





Domain of the equation: 5(x-2))!=0

x∈R



We calculate fractions


(5xx/(3(2x-5)*5(x-2)))+(-6x2/(3(2x-5)*5(x-2)))+5=0



We calculate terms in parentheses: +(5xx/(3(2x-5)*5(x-2))), so:

5xx/(3(2x-5)*5(x-2))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)





We calculate terms in parentheses: +(-6x2/(3(2x-5)*5(x-2))), so:

-6x2/(3(2x-5)*5(x-2))

We multiply all the terms by the denominator


-6x2

We add all the numbers together, and all the variables

-6x^2

Back to the equation:

+(-6x^2)



We get rid of parentheses

-6x^2+5xx+5=0

We move all terms containing x to the left, all other terms to the right

-6x^2+5xx=-5

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