(4/3)(2x-1)=-12

Solution for (4/3)(2x-1)=-12 equation:

(4/3)(2x-1)=-12

We move all terms to the left:

(4/3)(2x-1)-(-12)=0


Domain of the equation: 3)(2x-1)!=0

x∈R


We add all the numbers together, and all the variables

(+4/3)(2x-1)-(-12)=0

We add all the numbers together, and all the variables

(+4/3)(2x-1)+12=0

We multiply parentheses ..

(+8x^2+4/3*-1)+12=0

We multiply all the terms by the denominator


(+8x^2+4+12*3*-1)=0

We get rid of parentheses

8x^2+4-1+12*3*=0

We add all the numbers together, and all the variables

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$