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8x^2-49x+45=0
a = 8; b = -49; c = +45;
Δ = b2-4ac
Δ = -492-4·8·45
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-31}{2*8}=\frac{18}{16} =1+1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+31}{2*8}=\frac{80}{16} =5 $
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