(4/15)x=2/5

Solution for (4/15)x=2/5 equation:

(4/15)x=2/5

We move all terms to the left:

(4/15)x-(2/5)=0


Domain of the equation: 15)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/15)x-(+2/5)=0

We multiply parentheses

4x^2-(+2/5)=0

We get rid of parentheses

4x^2-2/5=0

We multiply all the terms by the denominator


4x^2*5-2=0

Wy multiply elements

20x^2-2=0

a = 20; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·20·(-2)
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{10}}{2*20}=\frac{0-4\sqrt{10}}{40}
=-\frac{4\sqrt{10}}{40}
=-\frac{\sqrt{10}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{10}}{2*20}=\frac{0+4\sqrt{10}}{40}
=\frac{4\sqrt{10}}{40}
=\frac{\sqrt{10}}{10}
$