10x-21=2(x-5)+8

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Solution for 10x-21=2(x-5)+8 equation: 



10x-21=2(x-5)+8

We move all terms to the left:

10x-21-(2(x-5)+8)=0



We calculate terms in parentheses: -(2(x-5)+8), so:

2(x-5)+8

We multiply parentheses

2x-10+8

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We get rid of parentheses

10x-2x+2-21=0

We add all the numbers together, and all the variables

8x-19=0

We move all terms containing x to the left, all other terms to the right

8x=19

x=19/8

x=2+3/8

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