(4.8-2x)/8=(0.4+x)/10

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Solution for (4.8-2x)/8=(0.4+x)/10 equation: 



(4.8-2x)/8=(0.4+x)/10

We move all terms to the left:

(4.8-2x)/8-((0.4+x)/10)=0

We add all the numbers together, and all the variables

(-2x+4.8)/8-((x+0.4)/10)=0

We calculate fractions


(-2x)/()+(-((x+0.4)*8)/()=0



We calculate terms in parentheses: +(-((x+0.4)*8)/(), so:

-((x+0.4)*8)/(

We multiply all the terms by the denominator


-((x+0.4)*8)



We calculate terms in parentheses: -((x+0.4)*8), so:

(x+0.4)*8

We multiply parentheses

8x+3.2

Back to the equation:

-(8x+3.2)



We get rid of parentheses

-8x-3.2

Back to the equation:

+(-8x-3.2)



We get rid of parentheses

(-2x)/()-8x-3.2=0

We multiply all the terms by the denominator


(-2x)-8x*()-(3.2)*()=0

We add all the numbers together, and all the variables

(-2x)-8x*()=0

We get rid of parentheses

-2x-8x*()=0

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