(4-y)/(5)=(2-2y)/(8)

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Solution for (4-y)/(5)=(2-2y)/(8) equation: 



(4-y)/(5)=(2-2y)/(8)

We move all terms to the left:

(4-y)/(5)-((2-2y)/(8))=0

We add all the numbers together, and all the variables

(-1y+4)/5-((-2y+2)/8)=0

We calculate fractions


(-y)/()+(-((-2y+2)*5)/()=0



We calculate terms in parentheses: +(-((-2y+2)*5)/(), so:

-((-2y+2)*5)/(

We multiply all the terms by the denominator


-((-2y+2)*5)



We calculate terms in parentheses: -((-2y+2)*5), so:

(-2y+2)*5

We multiply parentheses

-10y+10

Back to the equation:

-(-10y+10)



We get rid of parentheses

10y-10

Back to the equation:

+(10y-10)



We add all the numbers together, and all the variables

(-1y)/()+(10y-10)=0

We get rid of parentheses

(-1y)/()+10y-10=0

We multiply all the terms by the denominator


(-1y)+10y*()-10*()=0

We add all the numbers together, and all the variables

(-1y)+10y*()=0

We get rid of parentheses

-1y+10y*()=0

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