(4+7i)+(-3+5i)=1+12i

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Solution for (4+7i)+(-3+5i)=1+12i equation: 


Simplifying
(4 + 7i) + (-3 + 5i) = 1 + 12i

Remove parenthesis around (4 + 7i)
4 + 7i + (-3 + 5i) = 1 + 12i

Remove parenthesis around (-3 + 5i)
4 + 7i + -3 + 5i = 1 + 12i

Reorder the terms:
4 + -3 + 7i + 5i = 1 + 12i

Combine like terms: 4 + -3 = 1
1 + 7i + 5i = 1 + 12i

Combine like terms: 7i + 5i = 12i
1 + 12i = 1 + 12i

Add '-1' to each side of the equation.
1 + -1 + 12i = 1 + -1 + 12i

Combine like terms: 1 + -1 = 0
0 + 12i = 1 + -1 + 12i
12i = 1 + -1 + 12i

Combine like terms: 1 + -1 = 0
12i = 0 + 12i
12i = 12i

Add '-12i' to each side of the equation.
12i + -12i = 12i + -12i

Combine like terms: 12i + -12i = 0
0 = 12i + -12i

Combine like terms: 12i + -12i = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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