(3x-1)/7=(2x+3)/10

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Solution for (3x-1)/7=(2x+3)/10 equation: 


x in (-oo:+oo)

(3*x-1)/7 = (2*x+3)/10 // - (2*x+3)/10

(3*x-1)/7-((2*x+3)/10) = 0

(3*x-1)/7+(-1*(2*x+3))/10 = 0

(10*(3*x-1))/(7*10)+(-1*7*(2*x+3))/(7*10) = 0

10*(3*x-1)-1*7*(2*x+3) = 0

16*x-31 = 0

(16*x-31)/(7*10) = 0

(16*x-31)/(7*10) = 0 // * 7*10

16*x-31 = 0

16*x-31 = 0 // + 31

16*x = 31 // : 16

x = 31/16

x = 31/16

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