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(4+5i)=(4+5i)
We move all terms to the left:
(4+5i)-((4+5i))=0
We add all the numbers together, and all the variables
(5i+4)-((5i+4))=0
We get rid of parentheses
5i-((5i+4))+4=0
We calculate terms in parentheses: -((5i+4)), so:We get rid of parentheses
(5i+4)
We get rid of parentheses
5i+4
Back to the equation:
-(5i+4)
5i-5i-4+4=0
We add all the numbers together, and all the variables
=0
i=0/1
i=0
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