43=-4x-2(3x-5)-7

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Solution for 43=-4x-2(3x-5)-7 equation: 



43=-4x-2(3x-5)-7

We move all terms to the left:

43-(-4x-2(3x-5)-7)=0



We calculate terms in parentheses: -(-4x-2(3x-5)-7), so:

-4x-2(3x-5)-7

We multiply parentheses

-4x-6x+10-7

We add all the numbers together, and all the variables

-10x+3

Back to the equation:

-(-10x+3)



We get rid of parentheses

10x-3+43=0

We add all the numbers together, and all the variables

10x+40=0

We move all terms containing x to the left, all other terms to the right

10x=-40

x=-40/10

x=-4

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