(4+3x*2)+(x+6*2)=32

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Solution for (4+3x*2)+(x+6*2)=32 equation: 



(4+3x*2)+(x+6*2)=32

We move all terms to the left:

(4+3x*2)+(x+6*2)-(32)=0

We add all the numbers together, and all the variables

(3x*2+4)+(x+12)-32=0

We get rid of parentheses

3x*2+x+4+12-32=0

We add all the numbers together, and all the variables

x+3x*2-16=0

Wy multiply elements

x+6x-16=0

We add all the numbers together, and all the variables

7x-16=0

We move all terms containing x to the left, all other terms to the right

7x=16

x=16/7

x=2+2/7

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