2(x-2)+7(x+3)=9x+17

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Solution for 2(x-2)+7(x+3)=9x+17 equation: 



2(x-2)+7(x+3)=9x+17

We move all terms to the left:

2(x-2)+7(x+3)-(9x+17)=0

We multiply parentheses

2x+7x-(9x+17)-4+21=0

We get rid of parentheses

2x+7x-9x-17-4+21=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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