(4+2b)+(8+3c)=

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Solution for (4+2b)+(8+3c)= equation:


Simplifying
(4 + 2b) + (8 + 3c) = 0

Remove parenthesis around (4 + 2b)
4 + 2b + (8 + 3c) = 0

Remove parenthesis around (8 + 3c)
4 + 2b + 8 + 3c = 0

Reorder the terms:
4 + 8 + 2b + 3c = 0

Combine like terms: 4 + 8 = 12
12 + 2b + 3c = 0

Solving
12 + 2b + 3c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + 2b + -12 + 3c = 0 + -12

Reorder the terms:
12 + -12 + 2b + 3c = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 2b + 3c = 0 + -12
2b + 3c = 0 + -12

Combine like terms: 0 + -12 = -12
2b + 3c = -12

Add '-3c' to each side of the equation.
2b + 3c + -3c = -12 + -3c

Combine like terms: 3c + -3c = 0
2b + 0 = -12 + -3c
2b = -12 + -3c

Divide each side by '2'.
b = -6 + -1.5c

Simplifying
b = -6 + -1.5c

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