(x-3)/(2x-6)=2

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Solution for (x-3)/(2x-6)=2 equation: 


D( x )

2*x-6 = 0

2*x-6 = 0

2*x-6 = 0

2*x-6 = 0 // + 6

2*x = 6 // : 2

x = 6/2

x = 3

x in (-oo:3) U (3:+oo)

(x-3)/(2*x-6) = 2 // - 2

(x-3)/(2*x-6)-2 = 0

(x-3)/(2*x-6)+(-2*(2*x-6))/(2*x-6) = 0

x-2*(2*x-6)-3 = 0

9-3*x = 0

(9-3*x)/(2*x-6) = 0

(9-3*x)/(2*x-6) = 0 // * 2*x-6

9-3*x = 0

9-3*x = 0 // - 9

-3*x = -9 // : -3

x = -9/(-3)

x = 3

x in { 3} 

x belongs to the empty set

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