(4(x+4))/8=3x-3

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Solution for (4(x+4))/8=3x-3 equation: 



(4(x+4))/8=3x-3

We move all terms to the left:

(4(x+4))/8-(3x-3)=0

We get rid of parentheses

(4(x+4))/8-3x+3=0

We multiply all the terms by the denominator


(4(x+4))-3x*8+3*8=0



We calculate terms in parentheses: +(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

+(4x+16)



We add all the numbers together, and all the variables

(4x+16)-3x*8+24=0

Wy multiply elements

(4x+16)-24x+24=0

We get rid of parentheses

4x-24x+16+24=0

We add all the numbers together, and all the variables

-20x+40=0

We move all terms containing x to the left, all other terms to the right

-20x=-40

x=-40/-20

x=+2

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