(3z+13)/5=(5z+3)/6

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Solution for (3z+13)/5=(5z+3)/6 equation: 



(3z+13)/5=(5z+3)/6

We move all terms to the left:

(3z+13)/5-((5z+3)/6)=0

We calculate fractions


3z/()+(-((5z+3)*5)/()=0



We calculate terms in parentheses: +(-((5z+3)*5)/(), so:

-((5z+3)*5)/(

We multiply all the terms by the denominator


-((5z+3)*5)



We calculate terms in parentheses: -((5z+3)*5), so:

(5z+3)*5

We multiply parentheses

25z+15

Back to the equation:

-(25z+15)



We get rid of parentheses

-25z-15

Back to the equation:

+(-25z-15)



We get rid of parentheses

3z/()-25z-15=0

We multiply all the terms by the denominator


3z-25z*()-15*()=0

We add all the numbers together, and all the variables

3z-25z*()=0

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