(3y-4)+(y+20)=20

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Solution for (3y-4)+(y+20)=20 equation:


Simplifying
(3y + -4) + (y + 20) = 20

Reorder the terms:
(-4 + 3y) + (y + 20) = 20

Remove parenthesis around (-4 + 3y)
-4 + 3y + (y + 20) = 20

Reorder the terms:
-4 + 3y + (20 + y) = 20

Remove parenthesis around (20 + y)
-4 + 3y + 20 + y = 20

Reorder the terms:
-4 + 20 + 3y + y = 20

Combine like terms: -4 + 20 = 16
16 + 3y + y = 20

Combine like terms: 3y + y = 4y
16 + 4y = 20

Solving
16 + 4y = 20

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 4y = 20 + -16

Combine like terms: 16 + -16 = 0
0 + 4y = 20 + -16
4y = 20 + -16

Combine like terms: 20 + -16 = 4
4y = 4

Divide each side by '4'.
y = 1

Simplifying
y = 1

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