(Y/3)-(3/Y)=(16/3Y)

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Solution for (Y/3)-(3/Y)=(16/3Y) equation:


D( Y )

Y = 0

Y = 0

Y = 0

Y in (-oo:0) U (0:+oo)

Y/3-(3/Y) = (16/3)*Y // - (16/3)*Y

Y/3-((16/3)*Y)-(3/Y) = 0

Y/3+(-16/3)*Y-3*Y^-1 = 0

-5*Y^1-3*Y^-1 = 0

(-5*Y^2-3*Y^0)/(Y^1) = 0 // * Y^2

Y^1*(-5*Y^2-3*Y^0) = 0

Y^1

-5*Y^2-3 = 0

-5*Y^2-3 = 0

DELTA = 0^2-(-5*(-3)*4)

DELTA = -60

DELTA < 0

Y in { }

Y belongs to the empty set

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