(3y+6)=(5y-10)=(2y+4)

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Solution for (3y+6)=(5y-10)=(2y+4) equation: 



(3y+6)=(5y-10)=(2y+4)

We move all terms to the left:

(3y+6)-((5y-10))=0

We get rid of parentheses

3y-((5y-10))+6=0



We calculate terms in parentheses: -((5y-10)), so:

(5y-10)

We get rid of parentheses

5y-10

Back to the equation:

-(5y-10)



We get rid of parentheses

3y-5y+10+6=0

We add all the numbers together, and all the variables

-2y+16=0

We move all terms containing y to the left, all other terms to the right

-2y=-16

y=-16/-2

y=+8

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