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3(x-5)=2(x-5)-x
We move all terms to the left:
3(x-5)-(2(x-5)-x)=0
We multiply parentheses
3x-(2(x-5)-x)-15=0
We calculate terms in parentheses: -(2(x-5)-x), so:We get rid of parentheses
2(x-5)-x
We add all the numbers together, and all the variables
-1x+2(x-5)
We multiply parentheses
-1x+2x-10
We add all the numbers together, and all the variables
x-10
Back to the equation:
-(x-10)
3x-x+10-15=0
We add all the numbers together, and all the variables
2x-5=0
We move all terms containing x to the left, all other terms to the right
2x=5
x=5/2
x=2+1/2
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