(3y+15)=(1y+15)

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Solution for (3y+15)=(1y+15) equation: 



(3y+15)=(1y+15)

We move all terms to the left:

(3y+15)-((1y+15))=0

We add all the numbers together, and all the variables

(3y+15)-((y+15))=0

We get rid of parentheses

3y-((y+15))+15=0



We calculate terms in parentheses: -((y+15)), so:

(y+15)

We get rid of parentheses

y+15

Back to the equation:

-(y+15)



We get rid of parentheses

3y-y-15+15=0

We add all the numbers together, and all the variables

2y=0

y=0/2

y=0

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