(3y+1)=67

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Solution for (3y+1)=67 equation: 



(3y+1)=67

We move all terms to the left:

(3y+1)-(67)=0

We get rid of parentheses

3y+1-67=0

We add all the numbers together, and all the variables

3y-66=0

We move all terms containing y to the left, all other terms to the right

3y=66

y=66/3

y=22

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