2(2x+1)-5=10-3(x+2)

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Solution for 2(2x+1)-5=10-3(x+2) equation: 



2(2x+1)-5=10-3(x+2)

We move all terms to the left:

2(2x+1)-5-(10-3(x+2))=0

We multiply parentheses

4x-(10-3(x+2))+2-5=0



We calculate terms in parentheses: -(10-3(x+2)), so:

10-3(x+2)

determiningTheFunctionDomain
-3(x+2)+10

We multiply parentheses

-3x-6+10

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We add all the numbers together, and all the variables

4x-(-3x+4)-3=0

We get rid of parentheses

4x+3x-4-3=0

We add all the numbers together, and all the variables

7x-7=0

We move all terms containing x to the left, all other terms to the right

7x=7

x=7/7

x=1

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