(3y+1)=(6y-13)

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Solution for (3y+1)=(6y-13) equation: 



(3y+1)=(6y-13)

We move all terms to the left:

(3y+1)-((6y-13))=0

We get rid of parentheses

3y-((6y-13))+1=0



We calculate terms in parentheses: -((6y-13)), so:

(6y-13)

We get rid of parentheses

6y-13

Back to the equation:

-(6y-13)



We get rid of parentheses

3y-6y+13+1=0

We add all the numbers together, and all the variables

-3y+14=0

We move all terms containing y to the left, all other terms to the right

-3y=-14

y=-14/-3

y=4+2/3

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