(3y+1)=(8y-61)=(6y-13)

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Solution for (3y+1)=(8y-61)=(6y-13) equation: 



(3y+1)=(8y-61)=(6y-13)

We move all terms to the left:

(3y+1)-((8y-61))=0

We get rid of parentheses

3y-((8y-61))+1=0



We calculate terms in parentheses: -((8y-61)), so:

(8y-61)

We get rid of parentheses

8y-61

Back to the equation:

-(8y-61)



We get rid of parentheses

3y-8y+61+1=0

We add all the numbers together, and all the variables

-5y+62=0

We move all terms containing y to the left, all other terms to the right

-5y=-62

y=-62/-5

y=12+2/5

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