(3y)+52+(4y-4)=180

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Solution for (3y)+52+(4y-4)=180 equation: 



(3y)+52+(4y-4)=180

We move all terms to the left:

(3y)+52+(4y-4)-(180)=0

We add all the numbers together, and all the variables

3y+(4y-4)-128=0

We get rid of parentheses

3y+4y-4-128=0

We add all the numbers together, and all the variables

7y-132=0

We move all terms containing y to the left, all other terms to the right

7y=132

y=132/7

y=18+6/7

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