12.10+x=5(1/5x+2)

Solution for 12.10+x=5(1/5x+2) equation:

12.10+x=5(1/5x+2)

We move all terms to the left:

12.10+x-(5(1/5x+2))=0


Domain of the equation: 5x+2))!=0

x∈R


We add all the numbers together, and all the variables

x-(5(1/5x+2))+12.1=0

We multiply all the terms by the denominator


x*5x+(12.1)*5x+2))-(5(1+2))=0

We add all the numbers together, and all the variables

x*5x+(12.1)*5x+2))-(53)=0

We add all the numbers together, and all the variables

x*5x+(12.1)*5x=0

We multiply parentheses

x*5x+60.5x=0

Wy multiply elements

5x^2+60.5x=0

a = 5; b = 60.5; c = 0;
Δ = b2-4ac
Δ = 60.52-4·5·0
Δ = 3660.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60.5)-\sqrt{3660.25}}{2*5}=\frac{-60.5-\sqrt{3660.25}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60.5)+\sqrt{3660.25}}{2*5}=\frac{-60.5+\sqrt{3660.25}}{10}
$