(3x2+5x+7)-(-4x2+3x-6=)

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Solution for (3x2+5x+7)-(-4x2+3x-6=) equation: 



(3x^2+5x+7)-(-4x^2+3x-6=)

We move all terms to the left:

(3x^2+5x+7)-(-4x^2+3x-6-())=0

We get rid of parentheses

-(-4x^2+3x-6-())+3x^2+5x+7=0



We calculate terms in parentheses: -(-4x^2+3x-6-()), so:

-4x^2+3x-6-()

We add all the numbers together, and all the variables

-4x^2+3x

Back to the equation:

-(-4x^2+3x)



We add all the numbers together, and all the variables

3x^2-(-4x^2+3x)+5x+7=0

We get rid of parentheses

3x^2+4x^2-3x+5x+7=0

We add all the numbers together, and all the variables

7x^2+2x+7=0

a = 7; b = 2; c = +7;
Δ = b2-4ac
Δ = 22-4·7·7
Δ = -192
Delta is less than zero, so there is no solution for the equation

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