3-4x(2x-3)=2(3x+4)+1

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Solution for 3-4x(2x-3)=2(3x+4)+1 equation: 



3-4x(2x-3)=2(3x+4)+1

We move all terms to the left:

3-4x(2x-3)-(2(3x+4)+1)=0

We multiply parentheses

-8x^2+12x-(2(3x+4)+1)+3=0



We calculate terms in parentheses: -(2(3x+4)+1), so:

2(3x+4)+1

We multiply parentheses

6x+8+1

We add all the numbers together, and all the variables

6x+9

Back to the equation:

-(6x+9)



We get rid of parentheses

-8x^2+12x-6x-9+3=0

We add all the numbers together, and all the variables

-8x^2+6x-6=0

a = -8; b = 6; c = -6;
Δ = b2-4ac
Δ = 62-4·(-8)·(-6)
Δ = -156
Delta is less than zero, so there is no solution for the equation

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