(3x/3)=(0/3)2x-12=0

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Solution for (3x/3)=(0/3)2x-12=0 equation: 



(3x/3)=(0/3)2x-12=0

We move all terms to the left:

(3x/3)-((0/3)2x-12)=0



Domain of the equation: 3)2x-12)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3x/3)-(02x-12)=0

We get rid of parentheses

3x/3-02x+12=0

We multiply all the terms by the denominator


3x-02x*3+12*3=0

We add all the numbers together, and all the variables

3x-02x*3+36=0

Wy multiply elements

3x-6x+36=0

We add all the numbers together, and all the variables

-3x+36=0

We move all terms containing x to the left, all other terms to the right

-3x=-36

x=-36/-3

x=+12

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