2(m-3)+6m=3(9-m)

Solution for 2(m-3)+6m=3(9-m) equation:

2(m-3)+6m=3(9-m)

We move all terms to the left:

2(m-3)+6m-(3(9-m))=0

We add all the numbers together, and all the variables

2(m-3)+6m-(3(-1m+9))=0

We add all the numbers together, and all the variables

6m+2(m-3)-(3(-1m+9))=0

We multiply parentheses

6m+2m-(3(-1m+9))-6=0


We calculate terms in parentheses: -(3(-1m+9)), so:

3(-1m+9)

We multiply parentheses

-3m+27

Back to the equation:

-(-3m+27)


We add all the numbers together, and all the variables

8m-(-3m+27)-6=0

We get rid of parentheses

8m+3m-27-6=0

We add all the numbers together, and all the variables

11m-33=0

We move all terms containing m to the left, all other terms to the right

11m=33

m=33/11

m=3