(3x-x-10)=149

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Solution for (3x-x-10)=149 equation: 



(3x-x-10)=149

We move all terms to the left:

(3x-x-10)-(149)=0

We add all the numbers together, and all the variables

(2x-10)-149=0

We get rid of parentheses

2x-10-149=0

We add all the numbers together, and all the variables

2x-159=0

We move all terms containing x to the left, all other terms to the right

2x=159

x=159/2

x=79+1/2

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